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### Assume that the density of the solution is 101 g mL ,

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Go to Molarity Problems #11-25 Go to Molarity Problems #26-35 As should be clear from its name, molarity involves mol Boy, does it! The molarity of a solution is calculated by taking the moles of solute and dividing by the liters of solution This is probably easiest to explain with exampl Example #1: Suppose we had 100 mole of ,...

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In Part 1, when you are making the solution of KHP, why can't you use a spatula or scoopula to transfer the KHP to the flask? 3 In Part 1, when you are adding water to the KHP, why must you start over if you add a little too much water? Procedure Rinse out a 125 mL flask with deionized water and leave it open in your locker so that it has time ,...

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To get the molarity, you divide the moles of solute by the litres of solution #"Molarity" = "moles of solute"/"litres of solution"# For example, a 025 mol/L NaOH solution contains 025 mol of sodium hydroxide in every litre of solution...

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Chemisry of Solutions, Part 1 of 7 Solutions play a very important role in Chemistry because they allow intimate and varied encounters between molecules of different kinds, a condition that is essential for rapid chemical reactions to occur...

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Now let's make a 10% solution We know from the previous step that a 1:9 ratio of saturated solution to water will produce a 10% solution We also know that we want 500 mL of the solution ( in this case ) so we just need to calculate the size of each "part" Because we know that we are using a 1:9 ....

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### Chapter 13 Practice Questionstst - TestGen

10)A sample of potassium nitrate (490 g) is dissolved in 101 g of water at 100 °C, with precautions taken to avoid evaporation of any water The solution is cooled to 300 °C and a small amount of...

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Dec 05, 2013· Calculate [OH−] given [H3O+] in each aqueous solution Part A [H3O+] = 38×10−3M Express your answer using two significant figur Classify this solution as acidic or basic...

### Molecular Biology of Life Laboratory BIOL 123

Set up the problem as 5 ml serum + X ml saline = 25 ml of the final solution X = 25 - 5 X = 20 ml of saline The serum dilution is the amount of serum in the amount of total solution; hence, this is a 5/25 serum dilution which would equal a 1/5 dilution Molecular Biology of Life Laboratory BIOL 123 Dr Eby Bassiri [email protected] 2 ,...

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25 mg/ ml solution needed Remember that the amount of solvent used is based upon the final volume needed, so you have to subtract the starting volume form the final to calculate it Top of page 4 Moles and Molar solutions (unit = M = moles/L) Sometimes it may be more efficient to use molarity when calculating concentrations A mole is ,...

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### Preparing Chemical Solutions - The Science Company

Preparing Chemical Solutions; Preparing Chemical Solutions Lab experiments and types of research often require preparation of chemical solutions in their procedure We look at preparation of these chemical solutions by weight (w/v) and by volume (v/v) The glossary below cites definitions to know when your work calls for making these and the most accurate molar solutions,...

### Sodium hypochlorite - Wikipedia

Sodium hypochlorite solutions have been used to treat dilute cyanide waste water, , NaOH) as part of the manufacturing reaction Skin contact will produce caustic irritation or burns due to defatting and saponification of skin oils and destruction of tissue The slippery feel of bleach on skin is due to this process A European study, published in 2008, indicated that sodium hypochlorite ,...